How Fast Does Hot Water Cool When Sitting in Pipes?

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From the School of Hard Knocks.  Last updated Nov 18, 2007


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When you turn on the hot water at the kitchen faucet the water can take anywhere from a few seconds to a minute to get fully up to temperature. This is because hot water must make its way from the hot water tank through the pipes to the faucet. When you turn off the faucet hot water is left sitting in the pipes and immediately begins to cool. If you come back 10 minutes later then how much will it have cooled?

We can answer this question in two different ways. Either we can do an experiment to measure the water temperature directly, or we can use an equation called Newton's Law of Cooling to predict the water temperature. In practice it is useful to take both approaches as we can gain insights from each.

Start with Newton's Law of Cooling:

Newton's Law of Cooling states that the hotter an object is, the faster it cools. Please see the web page on this site called Newton's Law of Cooling for a full explanation of the equation and how it is derived.

The basic equation for Newton's Law of Cooling applied to water pipes is:

     T(t) = TA + (TH-TA) e-A/((mwcw+mpcp)R) t

     where
       T(t) = Temperature of water at time t
       TA = Air temperature surrounding the pipe, in Fahrenheit
       TH = Initial temperature of the hot water
       A = Surface area in square feet
       mw = mass of water in pounds
       cw = specific heat of water in btus/lb/F
       mp = mass of pipe in pounds
       cp = specific heat of pipe in btus/lb/F
       t = time in hours
       R = R-value of the insulation in ft2hrF/btu

Sample Calculation:

As a simple example, suppose 120F water sits in a 1/2 inch diameter CPVC pipe with R-2 insulation and the surrounding air temperature is 60F. What is the water temperature after 10 minutes?

Let's consider a 1 foot long section of pipe. As preliminaries we need to compute the surface area of the pipe and the mass of water in the pipe.

Surface Area of the Pipe Section:
The actual diameter of a 1/2 inch diameter CPVC pipe is about 1.2 cm, which converts to .4724 inches. The formula for surface area of a cylinder is:

     S = circumference x height = 3.14*diameter * height
     S = 3.14*.4724 inches * 12 inches / 144 in/ft2
     S = 0.124 ft2

Mass of Water in the Pipe:
We must first compute the volume of water in the pipe in order to compute the mass. The formula for the volume of a cylinder is:

     V = 3.14*radius2 * length
     V = 3.14*.23622 * 12
     V = 2.103 in3

Converting this volume in cubic inches to gallons:

     V = 2.103 in3 * 1 gallon/231 in3
     V = 0.009103 gallons

Converting this volume in gallons to pounds:

     m = 0.009103 gallons * 8.34 lb/gallon
     m = 0.07592 lb

Mass of 1 foot section of CPVC Pipe:
We cannot ignore the pipe itself, as that weighs about as much as the water inside it. I cut a 1 foot length of pipe and weighed it as 35 grams, which converts to 0.07716 pounds.

Summarizing the inputs:
       TH = 120 F
       TA = 60 F
       A = 0.124 ft2
       mw = 0.07592 lb
       cw = 1 btu/lb/F for water
       mp = 0.07716 lb
       cp = 0.20 btu/lb/F for CPVC pipe
       R = 2

So the coefficient A/((mwcw+mpcp)R = 0.124/(0.09135*2) = 0.6787

Substituting into the equation:

     T(t) = 60 + (120 - 60)e-0.6787 t

Setting t=1/6 hour (10 minutes):

     T(1/6) = 113.6 F

Thus the hot water temperature should theoretically drop 6.4 degrees F in 10 minutes. (I think the actual rate of temperature drop is much higher than suggested by this calculation.) With R-4 insulation the temperature after 10 minutes should be 116.7 F, or a 3.3 degree drop. So using higher quality insulation causes the water to stay hot longer and means there is less need to run new hot water from the tank if the last time you used the hot water was a few minutes ago.

What if there were no insulation on the pipe? We cannot plug R=0 into the equation or it won't work. In practice there are surface effects that provide an R-value on the order of 1 even with no insulation. We would have to perform an experiment to determine the exact "no insulation" R-value. Even then the R-value may depend on pipe orientation.

Empirical Measurement of Cooling:

This will have to wait until January, when our basement temperature is at its coldest.

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Copyright © 2008 Malcolm Shealy